2x^2+4y=20

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Solution for 2x^2+4y=20 equation:


Simplifying
2x2 + 4y = 20

Solving
2x2 + 4y = 20

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4y' to each side of the equation.
2x2 + 4y + -4y = 20 + -4y

Combine like terms: 4y + -4y = 0
2x2 + 0 = 20 + -4y
2x2 = 20 + -4y

Divide each side by '2'.
x2 = 10 + -2y

Simplifying
x2 = 10 + -2y

Reorder the terms:
-10 + x2 + 2y = 10 + -2y + -10 + 2y

Reorder the terms:
-10 + x2 + 2y = 10 + -10 + -2y + 2y

Combine like terms: 10 + -10 = 0
-10 + x2 + 2y = 0 + -2y + 2y
-10 + x2 + 2y = -2y + 2y

Combine like terms: -2y + 2y = 0
-10 + x2 + 2y = 0

The solution to this equation could not be determined.

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